Largest number formed by sum and product of digits. Given a range, say 0 − 100 0 − 100, what is the largest number formed by both adding or multiplying the digits? The answer here is 9 ∗ 9 9 ∗ 9, actually 9n 9 n, where n is the number of zeros in the upper range. So, for 100 − 10000 100 − 10000 the largest is 9 ∗ 9 ∗ 9 ∗ 9 9 Numbers, Numerals and Digits. Number. A number is a count or measurement that is really an idea in our minds. We write or talk about numbers using numerals such as "4" or "four". But we could also hold up 4 fingers, or tap the ground 4 times. These are all different ways of referring to the same number. Problema Solution. I am thinking of a 4-digit number. The sum of the digit is 27. The largest digit is used twice but not side by side. The smallest digit is in the largest place. The smallest digit is 1/3 as large as the largest digit. A factor is a whole number that can be divided evenly into another number. The first few prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29. Numbers that have more than two factors are called composite numbers. The number 1 is neither prime nor composite. For every prime number p, there exists a prime number p' such that p' is greater than p. The difference between four digit smallest and three digit largest number is 1. Step-by-step explanation: To find the difference between 4 digit smallest and 3 digit largest number, Let us take, The 4 digit number which is smallest as 1000 And then, The 3 digit number which is greatest as 999 Therefore, using given 4-digit numbers to form the greatest and smallest 3-digit number without repeating a digit. The numbers are 975 and 257. (ii) The given four-digit numbers are 6, 1, 4, 2 Now, we need to write the three-digit greatest and smallest number without repeating a digit on given four-digit numbers. The largest number of four digits exactly divisible by 88 . Concept used. Divisibility and remainder. Calculation. The largest four digit number is 9999. When we divide 9999 by 88 we get 55 as remainder. Substract the ramainder from the Dividend. ⇒ 9999 - 55 = 9944. The number exactly divisible by 88 is 9944 9867312 AWK Base 10. Ruling out 9- and 8-digit numbers (see first paragraph in the Raku example), we are looking for 7-digit numbers. In order to be a solution such a number has to be divisible by 12 = 2*2*3, because its digits must contain at least 2 of the numbers 2, 4, 6, 8 (leading to a factor of 2*2) and its digits must contain at least one of the numbers 3, 6, 9 (leading to a factor of 3). 2-digit number × 2-digit number = 4-digit number. To find the biggest 4-digit number which is a perfect square, we have to take the square of biggest 2-digit number. Calculation: 2-digit biggest number = 99. 99 2 = 9801. ∴ The biggest 4-digit number which is a perfect square = 9801. Create an array rightMax []. rightMax [i] contains the index of the greatest digit which is on the right side of num [i] and also greater than num [i]. If no such digit exists then rightMax [i] = -1. Now, traverse the rightMax [] array from i = 0 to n-1 (where n is the total number of digits in num ), and find the first element having rightMax MpITp.